GROMACS 4.6 example: Ethanol solvation with expanded ensemble

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Setting up the calculation with GROMACS

This tutorial assumes knowledge of [GROMACS]. Make sure you actually know how to use GROMACS first.

Setting up the calculations are very similar to standard free energy calculations; you can review a tutorial here for the standard way to perform the simulation. The topology and gro files are exactly the same; only the mdp files and the calls to the programs change.

In this particular case, we again set up nine intermediate states defined to perform the calculation of the absolute solvation free energy of ethanol (also known as the chemical potential at infinite dilution). However, you will only need to run one simulations, as the simulation will go back and forth between the different states.

So, start with the same (ethanol.gro) and (ethanol.top) and a new mdp file (expanded.mdp) files.

Running the calculation with GROMACS

Run grompp and mdrun as normal. Specifically:

  grompp -f expanded.mdp -c ethanol.gro -p ethanol.top -o ethanol.tpr -maxwarn 4

There may be some warnings, and you'll need to override, hence -maxwarn.

For mdrun, we simply run:

    mdrun -deffnm ethanol -dhdl ethanol.dhdl.xvg

The number of threads can be set as with any other simulation. If you don't set the dhdl file independently, it will be saved to ethanol.xvg,


Strictly, you will only need the dhdl files, but looking at the other output files can be useful to determine what is going on in the system if something goes wrong.

Analyze the calculation results

There are two ways to use the outputs to perform free energy calculations.

Expanded ensemble calculations build up the free energies as the simulations are performed. It does this by building up simulation weights as the simulation progresses, so each different thermodynamic state (lambda state) has a different weight. If it didn't have this weight, then the simulation would spend all the time in the lowest free energy states. When it visits each state equally, then the weights will be exactly equal to the free energies. We keep track of this in the log files. For example, after 50 ps, we have:

          Step           Time         Lambda
         25000       50.00000        0.00000
  
            MC-lambda information
 Wang-Landau incrementor is:           1
 N  CoulL   VdwL    Count   G(in kT)  dG(in kT)
 1  0.000  0.000       38    0.00000    4.00000   
 2  0.200  0.000       34    4.00000    4.00000   
 3  0.500  0.000       30    8.00000    0.00000   
 4  1.000  0.000       30    8.00000    3.00000   
 5  1.000  0.200       27   11.00000    3.00000 <<
 6  1.000  0.400       24   14.00000    1.00000   
 7  1.000  0.600       23   15.00000    2.00000   
 8  1.000  0.800       21   17.00000   -2.00000   
 9  1.000  1.000       23   15.00000    0.00000   

the << indicate the current state, with the free energies indicated.

at 250 ps, we have:

          Step           Time         Lambda
        125000      250.00000        0.00000
  
            MC-lambda information
 Wang-Landau incrementor is:      0.0625
 N  CoulL   VdwL    Count   G(in kT)  dG(in kT)
 1  0.000  0.000       13    0.00000    4.75000
 2  0.200  0.000       25    4.75000    3.87500
 3  0.500  0.000       41    8.62500    2.56250 <<
 4  1.000  0.000       30   11.18750    2.12500
 5  1.000  0.200       26   13.31250    1.62500
 6  1.000  0.400       24   14.93750    0.93750
 7  1.000  0.600       21   15.87500   -1.81250
 8  1.000  0.800        6   14.06250   -6.37500
 9  1.000  1.000        6    7.68750    0.00000

Note that the Wang-Landau incrementor (the amount added to the free energies of the current state) is now 0.0625

Much later, we reach:

          Step           Time         Lambda
        997000     1994.00000        0.00000
  
            MC-lambda information
 Wang-Landau incrementor is:   0.0078125
 N  CoulL   VdwL    Count   G(in kT)  dG(in kT)
 1  0.000  0.000      299    0.00000    4.53125
 2  0.200  0.000      311    4.53125    3.93750
 3  0.500  0.000      335    8.46875    1.96094
 4  1.000  0.000      340   10.42969    1.84375 <<
 5  1.000  0.200      352   12.27344    1.64844
 6  1.000  0.400      347   13.92188    0.64062
 7  1.000  0.600      383   14.56250   -2.22656
 8  1.000  0.800      450   12.33594   -5.54688
 9  1.000  1.000      456    6.78906    0.00000

And a few steps after that, we have:

 Step 998200: Weights have equilibrated, using criteria: wl-delta

So the weights now STOP equilibrating. From this point on, the simulation is an equilibrium simulation (it is not history-dependent). This is the point which we should START analyzing the dhdl file.

We can tell how close these free energies are by looking at how close the visits are to flat at the end of the simulation:

          Step           Time         Lambda
      20000000    40000.00000        0.00000
   
           MC-lambda information
 N  CoulL   VdwL    Count   G(in kT)  dG(in kT)
 1  0.000  0.000    24232    0.00000    4.50000
 2  0.200  0.000    21616    4.50000    3.98438
 3  0.500  0.000    20533    8.48438    1.96875
 4  1.000  0.000    21404   10.45312    1.84375
 5  1.000  0.200    20978   12.29688    1.64844
 6  1.000  0.400    24308   13.94531    0.64062 <<
 7  1.000  0.600    23005   14.58594   -2.22656
 8  1.000  0.800    17166   12.35938   -5.54688
 9  1.000  1.000    16776    6.81250    0.00000

We can see that the counts are within 2.42/1.68 = 1.44, and kBT*log(1.44) = 0.8 kJ/mol, which is not so bad since the weights were fixed after 2 ns of total simulation at all eight states.

We can now analyze the dhdl file, using pymbar with the dhdl output. Unlike last time, there is only one dhdl file, which has outputs of the form:

@ s0 legend "Thermodynamic state" 
@ s1 legend "Energy (kJ/mol)" 
@ s2 legend "dH/d\xl\f{} (coul -lambdas)"
@ s3 legend "dH/d\xl\f{} (vdw-lambdas)"
@ s4 legend "\xD\f{}H \xl\f{} (0,0)"
@ s5 legend "\xD\f{}H \xl\f{} (0.2,0)"
@ s6 legend "\xD\f{}H \xl\f{} (0.5,0)"
@ s7 legend "\xD\f{}H \xl\f{} (1,0)"
@ s8 legend "\xD\f{}H \xl\f{} (1,0.2)"
@ s9 legend "\xD\f{}H \xl\f{} (1,0.4)"
@ s10 legend "\xD\f{}H \xl\f{} (1,0.6)"
@ s11 legend "\xD\f{}H \xl\f{} (1,0.8)"
@ s12 legend "\xD\f{}H \xl\f{} (1,1)"
@ s13 legend "pV (kJ/mol)"
0.0000    0 -29136.337 63.503958 19.491314 0.0000000 12.700792 31.751979 63.503958 67.421648 71.375522 75.362115 79.378551 83.422410 1.6650634
0.2000    0 -29341.744 95.496064 -258.31621 0.0000000 19.099213 47.748032 95.496064 85.312750 85.791887 87.838454 90.571444 93.705941 1.6496685
0.4000    0 -28839.430 81.996287 8.7445649 0.0000000 16.399257 40.998143 81.996287 84.283621 87.281402 90.697714 94.393505 98.291373 1.6952030

The first line after the time is the thermodynamic state. We can then distinguish which state each sample is from.

Again you will need to install [[1]]. alchemical-gromacs.py will be in examples directory.

The correct invocation is:

  python alchemical-gromacs.py -f directory/prefix -t 300 -p 1 -n 2500 -v  > outpufile

'-t' is temperature, '-p' is pressure, '-f' is (prefix of the files, including directory), and '-v' is verbose output (not required, but helpful to understand!)

It will use all files it finds with the given prefix, and it will assume they are numbered in order. In this case, there should only be one file. If there are multiple expanded ensemble files, it will analyze all the data together. We should omit the first 2 ns, since we know that the weights were still equilibrating. Read over the usage for standard calculations.

Understanding the analysis

Let's look at the output file:

This time it's only reading a single file:

 The number of files read in for processing is:  1
 output is verbose
 Reading metadata from solvation_direct/outputs/dhdls/ethanol_expanded.dhdl.xvg...
 Done reading metadata from solvation_direct/outputs/dhdls/ethanol_expanded.dhdl.xvg...
 Reading solvation_direct/outputs/dhdls/ethanol_expanded.dhdl.xvg...

All standard stuff saying what it's doing. The next part is important. pymbar determines how many of the samples are statistically uncorrelated, and only uses every [math]\displaystyle{ 1/2\tau }[/math] samples. Although it says correlation time, it's really the twice the correlation time, which is the length of time required between uncorrelated samples.

  Now computing correlation times
 Correlation times:
 [ 5.00888473  5.00888473  5.00888473  5.00888473  5.00888473  5.00888473
   5.00888473  5.00888473  5.00888473]
   
 number of uncorrelated samples:
 [3417 3049 2913 3000 2940 3365 3211 2468 2407]


The convergence behaves just the same. We get the same format of outputs, because we are still sampling from 8 states.

      TI (kJ/mol)   TI-CUBIC (kJ/mol)       DEXP (kJ/mol)       IEXP (kJ/mol)        BAR (kJ/mol)       MBAR (kJ/mol)
   0:    11.478 +-  0.041   11.441 +-  0.043   11.405 +-  0.089   11.467 +-  0.091   11.408 +-  0.042   11.410 +-  0.041
   1:    10.274 +-  0.056   10.008 +-  0.065   10.042 +-  0.132   10.007 +-  0.174   10.032 +-  0.060   10.048 +-  0.057
   2:     5.463 +-  0.072    4.811 +-  0.104    5.049 +-  0.161    4.402 +-  0.226    4.736 +-  0.073    4.714 +-  0.059
   3:     4.682 +-  0.031    4.705 +-  0.033    4.948 +-  0.064    4.613 +-  0.029    4.609 +-  0.026    4.643 +-  0.017
   4:     3.687 +-  0.028    3.691 +-  0.032    3.720 +-  0.104    3.794 +-  0.033    3.762 +-  0.026    3.755 +-  0.021
   5:     1.503 +-  0.042    2.059 +-  0.048    1.947 +-  0.150    1.794 +-  0.054    1.792 +-  0.039    1.787 +-  0.037
   6:    -5.330 +-  0.068   -5.232 +-  0.075   -4.464 +-  0.409   -4.670 +-  0.187   -4.760 +-  0.090   -4.735 +-  0.089
   7:   -13.103 +-  0.068  -13.580 +-  0.082  -13.769 +-  0.127  -12.219 +-  1.090  -13.774 +-  0.066  -13.770 +-  0.066
------------------- ------------------- ------------------- ------------------- ------------------- -------------------
TOTAL:    18.653 +-  0.501   17.901 +-  0.539   18.878 +-  0.522   19.187 +-  1.148   17.803 +-  0.162   17.853 +-  0.191

We have almost identical results to the fixed lamda simulations, carried out with simulations at fixed states:

         TI (kJ/mol)   TI-CUBIC (kJ/mol)       DEXP (kJ/mol)       IEXP (kJ/mol)        BAR (kJ/mol)       MBAR (kJ/mol)
 ------------------- ------------------- ------------------- ------------------- ------------------- -------------------
 TOTAL:    18.505 +-  0.186   17.721 +-  0.198   17.559 +-  0.305   18.104 +-  0.361   17.688 +-  0.059   17.684 +-  0.070

We can ALSO compare to the weights at the point they were fixed. The free energies will be -1 times the weights time [math]\displaystyle{ k_B T }[/math] = 2.494 ( at T = 300 giving

   0: 11.22
   1:  9.94
   2:  4.91 
   3:  4.60
   4:  4.11
   5:  1.60
   6: -5.55
   7: -13.83
TOTAL:  16.99

Which are about 0.7 kJ/mol from the MBAR estimate, about the 0.8 kJ/mol we estimated earlier.

The uncertainties are lower with the fixed lambda states, which in this case is mostly because of different correlation times. For expanded ensembles, we take the correlation time in the total u_k(x), which behaves a bit differently that the correlation time in the derivative of the potential.

Hamilton replica exchange

There is no point in doing expanded ensemble with Hamiltonian replica exchange -- it's ALREADY visiting all of the states.